clock input divider
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@ -1,4 +1,4 @@
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EESchema-LIBRARY Version 2.3 Date: Thu May 17 11:03:28 2012
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EESchema-LIBRARY Version 2.3 Date: Thu May 17 11:31:07 2012
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#encoding utf-8
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#encoding utf-8
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#
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#
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# BALUN
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# BALUN
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@ -1,4 +1,4 @@
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EESchema Schematic File Version 2 date Thu May 17 11:03:28 2012
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EESchema Schematic File Version 2 date Thu May 17 11:31:07 2012
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LIBS:power
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LIBS:power
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LIBS:device
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LIBS:device
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LIBS:transistors
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LIBS:transistors
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@ -45,6 +45,17 @@ Comment2 ""
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Comment3 ""
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Comment3 ""
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Comment4 ""
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Comment4 ""
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$EndDescr
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$EndDescr
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Text Notes 4550 9550 0 40 ~ 0
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Clock input should be 1.1 to 3.3 V\npeak-to-peak. It is divided down to\n0.5 to 1.5 V (REF_IN).
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$Comp
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L C C?
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U 1 1 4FB3CC76
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P 6000 10050
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F 0 "C?" H 6050 10150 50 0000 L CNN
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F 1 "1nF" H 6050 9950 50 0000 L CNN
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1 6000 10050
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1 0 0 -1
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$EndComp
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Wire Wire Line
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Wire Wire Line
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13200 5800 13300 5800
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13200 5800 13300 5800
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Wire Wire Line
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Wire Wire Line
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@ -1026,15 +1037,6 @@ F 1 "GND" H 6000 10280 30 0001 C CNN
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1 0 0 -1
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1 0 0 -1
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$EndComp
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$EndComp
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$Comp
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$Comp
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L C C?
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U 1 1 4FB3CC76
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P 6000 10050
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F 0 "C?" H 6050 10150 50 0000 L CNN
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F 1 "DNP" H 6050 9950 50 0000 L CNN
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1 6000 10050
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1 0 0 -1
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$EndComp
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$Comp
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L GND #PWR?
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L GND #PWR?
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U 1 1 4FB3CC5E
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U 1 1 4FB3CC5E
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P 5800 9450
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P 5800 9450
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@ -1413,7 +1415,7 @@ L C C?
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U 1 1 4FAECD45
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U 1 1 4FAECD45
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P 6000 9450
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P 6000 9450
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F 0 "C?" H 6050 9550 50 0000 L CNN
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F 0 "C?" H 6050 9550 50 0000 L CNN
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F 1 "1nF" H 6050 9350 50 0000 L CNN
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F 1 "1.2nF" H 6050 9350 50 0000 L CNN
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1 6000 9450
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1 6000 9450
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1 0 0 -1
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1 0 0 -1
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$EndComp
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$EndComp
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